In England the currency is made up of pound, £, and pence, p, and there are eight coins in general circulation:
$1p, 2p, 5p, 10p, 20p, 50p, £1 (100p)$ and $£2 (200p)$.
It is possible to make £2 in the following way:
$$1×£1 + 1×50p + 2×20p + 1×5p + 1×2p + 3×1p$$
How many different ways can £2 be made using any number of coins?
coins = [1,2,5,10,20,50,100,200]
def findcoin(target, n):
if n <= 1:
return 1
res = 0
while target >= 0:
res+=findcoin(target,n-1)
target = target - coins[n-1]
return res
findcoin(200,8)